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X^2+6X+11/10=0
We multiply all the terms by the denominator
X^2*10+6X*10+11=0
Wy multiply elements
10X^2+60X+11=0
a = 10; b = 60; c = +11;
Δ = b2-4ac
Δ = 602-4·10·11
Δ = 3160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3160}=\sqrt{4*790}=\sqrt{4}*\sqrt{790}=2\sqrt{790}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{790}}{2*10}=\frac{-60-2\sqrt{790}}{20} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{790}}{2*10}=\frac{-60+2\sqrt{790}}{20} $
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